5x^2+27x=56

Solution for 5x^2+27x=56 equation:

5x^2+27x=56

We move all terms to the left:

5x^2+27x-(56)=0

a = 5; b = 27; c = -56;
Δ = b2-4ac
Δ = 272-4·5·(-56)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-43}{2*5}=\frac{-70}{10}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+43}{2*5}=\frac{16}{10}
=1+3/5
$